Anet force acts on a mass of 8.00 kg causing it to move from rest to a speed of 10.0 m/s in a time of 5.00 s. the bet force must have a magnitude of a.8.00n b.16.0n c.40.0n d.80.0n

Given data

mass (m) =8 Kg ,

speed (v) =10 m/s ,

time (t) = 5 s

determine magnitude of force (Fnet) = ?

                    we knoe that

                                        Fnet = m.a

                                                 = 8 × (v/t)       since a = v/t

                                                 = 8 × (10/5)

                                                 = 16 N

Magnitude of net force is 16 N

hey , the answer is c

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~