Adog pushes a toy horizontally on a frictionless floor with a net force of 2.0\, \text n2.0n for 1.0\,\text m1.0m. how much kinetic energy does the toy gain?

2.0 J

Explanation:

Since the surface is frictionless, we can solve the problem by using the work-energy theorem, which states that the work done on the toy is equal to the kinetic energy gained by the toy:

where

W is the work done on the toy

is the kinetic energy gained by the toy

The work done can be calculated as the product between the force applied on the toy and its displacement, so:

Therefore, according to the work-energy theorem, the toy has gained 2.0 J of kinetic energy.

6/12=1/2

step-by-step explanation: