3) a driver in a 1000-kg car traveling at 24 m/s slams on the brakes and skids to a stop. if the coefticient of friction between the tires and the level road is 0 80 how long will the skid marks be? a) 37 m b) 30 m c) 34 m d 46 m

A) 37 m

Explanation:

When the driver slams on the brakes, the force of friction acting on the car provides the deceleration that will cause the car to stop, according to Newton's second law:

where

is the coefficient of friction

m = 1000 kg is the mass of the car

g = 9.8 m/s^2

a is the deceleration

Substituting into the formula, we find the deceleration:

Now we can find the length of the skid with the SUVAT equation:

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

d is the length of the skid

Substituting, we find

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