A5.0 kilogram rock rolls off the edge of a cliff. if it is traveling at a speed of 24.2m/s when it hits the ground, what is the height of the cliff?

Using the kinematic equation ;

vf²=vi²+2ad just rearrange for d;

vf²-vi²=2ad;

(vf²-vi²)/2a=d

Now plug the numbers in.

vf=24.2

vi=0

a=9.81=g

(24.2²-0²)/(2*9.81)=29.8 m.

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer