You are given two positively charged particles, of equal magnitude, separated by a distance, "d". what will happen to the force field between the two particles when "d" is doubled? a) remain constant b) decrease by a factor of two c) decrease by a factor of four d) nothing; no force field between particles

force goes as 1/d^2 ... (2d)^2 => 4d^2 ...

C) decrease by a factor of four

Explanation :

There exists a force between charged particle given by Coulomb's law.

where,

k is the electrostatic constant

are charged particles

d is the distance between the charges.

When d is doubled (d' = 2d) , let F' be the force.

So, the force decrease by a factor of four.

Hence, the correct option is (C) "decrease by a factor of four".

mass and volume are the answers you are looking for

explanation:

wheres the pic