Can someone just show me how to work this out. for a home sound system, two small speakers are located so that one is 45cm closer the listener than the other. for what value of the fundamental frequency of audible sound will these speakers produce constructive interference at the listener? the speed of sound is 340m/sec a.764hz b.500hz c.900hz d.387hz

Δx = path difference between the waves from two speaker at the listener = difference in distance of speakers from the listener = 45 cm = 0.45 m

n =  1                     (for fundamental frequency )

λ = wavelength

v = speed of sound = 340 m/s

f = frequency of the sound = ?

using the condition for constructive interference

Δx = n λ

0.45 = 1 λ

λ = 0.45 m

frequency of sound is given as

f = v/λ

f = 340/0.45

f = 756 Hz

nearest choice is 764 Hz , hence the correct choice is A. 764 Hz

answer: (431,2)

step-by-step explanation:

come closer and become far apart and become steam/gas