What is the correct displacement for the following vectors: 4 km south, 2 km north, 5 km south, and 5 km north? 2 km south 16 km total 11 km west 6 km south

The correct answer option is: 2 km South.

Explanation:

We are to find out the displacement for the given vectors:

- 4 km south,

- 2 km north,

- 5 km south; and

- 5 km north

So starting off with the vector going 4 km south we have a displacement of 4 km south. Then it goes 2 km so we are left with 4 - 2 = 2 km south.

Next, it goes 5 km south so we will have a displacement of 2 + 5 = 7 km south. Then again it goes 5 km north so we are left with a displacement of 7 - 5 = 2 km South.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂