Achild sits on the edge of a spinning merry-go-round that has a radius of 1.2 m. the child's speed is 5 m/s. what is the child's acceleration?

Explanation:

The centripetal acceleration of the child, which is moving by uniform circular motion, is given by

where

v = 5 m/s is the tangential speed of the child

r = 1.2 m is the radius of the circular path

Substituting the numbers into the equation, we find

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explanation:

force tends to be low and long diustance masses are high