If the momentum of the nasa space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg*m/s and its mass is 7500 kg what is its speed

Velocity of the space velocity, v = 50,000 m/s

Explanation:

It is given that,

The momentum of the NASA space shuttle as it leaves the atmosphere is,

Mass of the space shuttle, m = 7500 kg

We need to find the speed of the NASA space. The momentum of an object is given by the product of mass of the object and its velocity.

p = mv

v = 50,000 m/s

So, the speed of the NASA space shuttle is 50,000 m/s. Hence, this is the required solution.

the velocity you are looking for is made up of two parts: horizontally velocity, vh, and its vertical velocity, vv. the actual velocity of the ball will be these two parts added together, and because velocity is a vector then they will need to be added vectorially.  

neglecting air resistance etc etc.,  

the horizontal velocity component will be constant (because there is no accelerating force in the horizontal direction.  

vh = 8 ms-1  

the vertical velocity component has an accelerating force: 'g'.  

using v = u +at where a = g = 9.81 ms-2.  

the vertical component of velocity, vv = 0 + gt = vv =9.81 x 2  

vv = 19.62 ms-1 . the zero appears because the virtical component of velocity at time t=0 is zero. remember, the ball was thrown horizontally.  

how fast it will be moving (it actual path (being a parabola )) will be the vector sum of these two.  

adding vectorally gives: -  

v = sqr root (8^2 + 19.62^2) = sqr root(64+384.9) = 21.18 or 21.2 ms-1