Aweightlifter raises a barbell of mass 100 kg from the floor to over his head ( 2.5 meters) in 2 seconds. what is his average power input? give ur answer in both watts and horse power

bear in mind that Gravitational capacity potential = mass * height * g. So, a) (i) artwork achieved = substitute in potential = a hundred * 9.80 two * 2 = 1964 J (ii) The sideways movements make no distinction to the terrific artwork achieved. the burden nonetheless finally ends up 2 m from the floor, so the comparable volume of artwork must be achieved. artwork achieved = 1964 J b) whilst the burden is released, its PE is switched over into Kinetic potential. So, on the instantaneous beforehand is hits his toe, we've 1964 = (a million/2) m v^2 v^2 = 1964 / (0.5 * a hundred) = 39.28 v = ?(39.28) = 6.27 m/s

like poles repel so keep pushing north to north and repels funny to see this

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )