Estimate the mass of water that must evaporate from the skin to cool the body by 0.55 ∘c. assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 j/g⋅∘c.

Heat required to decrease the temperature of body is given as

here given that

now by above equation

now in order to evaporate water the heat is given as

so 97 g of water will evaporate from the body

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures