If dot c moves to position 5 (60 meters), what is its average velocity during these 5 seconds? a) 10 m/s b) 11 m/s c) 12 m/s d) 13 m/s

C) 12 m/s

Explanation:

As we know that average velocity is given as ratio of displacement and time

so here we can say

now we have

now as per above formula we have

so the average velocity must be 12 m/s

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.