Apower source of 5 v is attached to the ends of a capacitor. the charge is 10 µc. what is the capacitance for this capacitor?

Given:

Voltage of source =  5 V

Charge on capacitor = 10 µC

To find:

Capacitance of the capacitor = ?

Formula used:

Charge on the capacitor is given by,

Q = C V

Where Q = charge

C = capacitance

V = voltage of source

Solution:

Charge on the capacitor is given by,

Q = C V

Where Q = charge

C = capacitance

V = voltage of source

C =

C = Farad

C = 2 µC

The charge on the capacitor is 2 µC.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach