Agun shoots a bullet with a velocity of 500 m/s. the gun is aimed horizontally and fired from a height of 1.5 m. how far does the bullet travel?

The bullet travels a horizontal distance of 276.5 m

The bullet is shot forward with a horizontal velocity . It takes a time t to fall a vertical distance y and at the same time travels a horizontal distance x.

The bullet's horizontal velocity remains constant since no force acts on the bullet in the horizontal direction.

The initial velocity of the bullet has no component in the vertical direction. As it falls through the vertical distance, it is accelerated due to the force of gravity.

Calculate the time taken for the bullet to fall through a vertical distance y using the equation,

Substitute 0 m/s for , 9.81 m/s²for g and 1.5 m for y.

The horizontal distance traveled by the bullet is given by,

Substitute 500 m/s for and 0.5530s for t.

The bullet travels a distance of 276.5 m.

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.