Ineed . question three (1 point) if a crests of two waves line up and double the height of the wave, what is happening? a) the wave is reflecting b) constructive interference is occurring c) destructive interference is occurring d) the wave is breaking

If a crests of two waves line up and double the height of the wave, they are said to be interfering constructively.

When two waves come across each other, they get superimposed. When two waves are super imposed, the resulting wave is the sum of the individual waves at that point. Sometimes, the waves are in phase with each other, i.e the crests and troughs of the waves coincide. When this happens, the resulting wave has a height that is double the height of the individual waves.

From this we can see that the correct answer for this question is (B), constructive interference is occurring.

a and c

c is 100% but i am confused in a

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.