Jill and scott both road their bikes for 30 minutes. jill traveled 5 kilometers and scott traveled 10. calculate each person's speed and tell who rode faster. (s=d/t) a)scott had the faster speed since he rode at 20 k/h while jill only traveled 10 km/h. b)scott had the faster speed since he rode at 10 km/h and jill was riding at 5 km/h c)jill was traveling faster. she was riding at a speed of 10 km/h while scott was traveling at 20 km/h. d)both jill and scott were traveling at the same speed since they both rode their bikes for 30 minutes.

time for which Jill and Scott both traveled is 30 min

as we know that

1 hour = 60 min

now we will convert the time of travel from minutes to hour

now we will have to find the speed of both

For speed we know the formula

speed of Jill as he cover 5 km in 30 min

speed of Scott as he cover 10 km in 30 min

so correct answer is

A)Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

the total distance traveled by the car is

30km + 49km = 79 km .