If a bullet leaves the muzzle of a rifle at 600.0 m/s, and the barrel is 0.90 m long, what was the acceleration of the bullet while in the barrel?

Use the kinematic vf^2 = vi^2 + 2a(x)

Using this, you get (600 m/s)^2 = (0m/s)^2 + 2a(.9m)

Solve for acceleration

a = 200,000 m/s^2

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multiple

do you have a formula possibly