Achair of weight 80.0 n lies atop a horizontal floor; the floor is not frictionless. you push on the chair with a force of f = 44.0 n directed at an angle of 43.0 ∘ below the horizontal and the chair slides along the floor. using newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair. express your answer in newtons.

The chair does not move along the vertical direction: this means that the net force on the vertical direction is zero.

There are three forces acting along the vertical direction:

- The weight, acting downward:

- The component of the force F perpendicular to the floor, acting downward:

- The normal force N, acting upwards.

Since the net force must be zero, we have:

From which we can find the value of N:

u

explanation: