If a block is in equilibrium the magnitude of the block's acceleration is

If a block is in equilibrium the magnitude of the block's acceleration is 0m/s²

According to Newton's second law, the force acting on a body is equal to the product of its mass and acceleration.

Mathematically F = ma where:

m is the mass of the object

a is the acceleration of the object

If a block is in equilibrium, the magnitude of the force acting on the block will be 0, that is F = 0

Substituting F = 0 into the formula above to calculate the acceleration;

F = ma

0 = ma

Swap sides

ma = 0

a =0/m

a = 0m/s²

This shows that if a block is in equilibrium the magnitude of the block's acceleration is 0m/s²

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zero.

Explanation:

The condition for an object to be in equilibrium is that there is no resulting force acting on it, in other words, that the force on the object is zero:

and by Newton's second law we know that

where is the mass of the object, and its acceleration.

So combining the two things:

⇒, This equation is fulfilled when

Wich tells us that for the the block to be in equilibrium, the acceleration must be zero:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2