Acat leaps into the air to catch a bird with an initial speed of 2.74 m/s at an angle of 60.0° above the ground. what is the highest point of the cat’s trajectory? a. 0.19 m b. 10.96 m c. 0.58 m d. 0.29 m

D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

  (1)

  (2)

Where:

 is the height of the cat  

is the cat's initial velocity

 is the acceleration due gravity

is the time

is the y-component of the velocity

Now the cat will have its maximum height when . So equation (2) is rewritten as:

  (3)

Finding :

  (4)

  (5)

  (6)

Substituting (6) in (1):

  (7)

Finally:

  (8)

its c its is a mixture of gases

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