Suppose a rocket launches with an acceleration of 34.0 m/s2 what is the apparent weight of an 85-kg astronaut aboard this rocket?

2057N

Explanation:

Mass (M) = 85kg

Acceleration (a) = 34.0m/s²

g = 9.8m/s²

Weight = mass * acceleration

Weight = 85 * 34 = 2890N

Force acting against the astronaut = M*g

F = 833N

Weight of the astronaut = weight of the astronaut inside the rocket (thrust) - force of gravity acting on him

Weight = Ma - Mg = M(a-g)

Weight = 2890 - 833 = 2057N

the apparent weight of the astronaut in the rocket is 3723 N.

Given:

acceleration = 34

mass of astronaut = 85 kg

To find:

Apparent weight of the astronaut = ?

Solution:

Total weight of the astronaut in a rocket is given by,

W = w + F

W = apparent weight of the astronaut

w = weight of astronaut on earth surface = mg

F = force acting on the astronaut = ma

W = mg+ma

W = m (g+a)

W = 85 (9.8 + 34)

W = 3723 N

Thus, the apparent weight of the astronaut in the rocket is 3723 N.

c. newton's third law of motion