My scooter can go from 0 to 25m/s in only 4.0s . what is the acceleration of the scooter ? ?

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) minus (speed at the beginning)

For your scooter . . .

Change in speed = (25 m/s) - (0) = 25 m/s

Time for the change = 4.0 seconds

Acceleration = (25 m/s) / (4.0 s)

Acceleration = (25/4) (m / s·s)

Acceleration = 6.25 m/s²

That's the acceleration the SCOOTER is capable of.  The next question is: Are YOU capable of that much acceleration, or do you go tumbling off the back ?

answer: cesare beccaria developed the classical school of criminology with from philosopher jeremy bentham

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s