An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenthesis equals 18 t squaredd(t)=18t^2 feet in the first t seconds. find the average rate of change of distance with respect to time as t changes from t 1t1equals=55 to t 2t2equals=99. this rate is known as the average velocity, or speed.

displacement is given by equation

now at t = 5 s the position is

similarly position at t = 9 s

so the displacement of object in given interval of time will be

time interval

now the average velocity will be given as

so its average speed is 252 m/s

all of the answers are correct.

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explanation:

a displacement distance is size of displ