Acertain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hits the ground. (a) find the velocity of the object when it is 30.0 m above the ground. (b) find the total distance the object travels during the fall.

We use the kinematic equation for vertical motion,

Here, , and .

Therefore, the initial velocity when the object is at height 30 m, from above equation

Now the displacement before the reaching the height 30.0 m above the ground, we use kinematic equation

Here, , because freely falling object, released from rest and and we take height -h because downward falling.

Substituting these values in above equation, we get

.

Therefore, the total distance the object travels during the fall,  s+h= 30 m+ 8.16 =38.16 m.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr