A3.5-cm radius hemisphere contains a total charge of 6.6 × 10–7 c. the flux through the rounded portion of the surface is 9.8 × 104 nm2/c. the flux through the flat base is:

The flux through the flat base is:

This states that the net flux of an electric field in a closed surface is directly proportional to the electric charge.

To calculate the flux through the flat base, we would make use of Gauss's Law

φ

We input the value of Q

Q= 6.6 x 10^-7C

Next, we make the addition

-9.8 x 10⁴ + 7.46 * 10⁴

=-2.34 * 10⁴N * m^2/C

Therefore, the flux through the flat base is given as -2.34 * 10⁴N * m^2/C

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As per Gauss Law

Net flux through enclosed surface is

here through this hemisphere total flux will pass through two portions

1). from the curved surface

2). from flat circular base

so now we have

given that

now we have

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.