An object initially at rest experiences an acceleration of 9.8 m/s2 how much time will it take it to achieve a velocity of 58 m/s

The time required by object to achieve velocity 58 m/s is 5.918 second.

Given:

acceleration = 9.8

Initial velocity = 0 m/s

final velocity = 58 m/s

To find:

Time required by object = ?

Formula used:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

Solution:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

58 = 0 + 9.8 (t)

t =

t = 5.918 s

The time required by object to achieve velocity 58 m/s is 5.918 second.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.