What is the magnitude of the momentum change of two gallons of water (inertia about 7.3 kg ) as it comes to a stop in a bathtub into which it is poured from a height of 2.0 m ?

We know that the change in momentum is equals to the product of force and time that is impulse (  ). Therefore, we need to determine the value of that the water is in air by using the second equation of motion,

Here, u is initial velocity which is zero.

.

Thus, impulse

From Newton`s second law,

Therefore, impulse

Given,   and

Substituting these values, we get

Change in momentum = impulse  

.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y