Asheet of gold foil has a volume of 0.750 cm3. if the foil measures 50.0cm by 10.0cm, what is the thickness of the foil?

To calculate the thickness of foil, we use formula of volume as

Here, l is the length of the foil, w is the width of the foil and t is the thickness of the foil.

Given,  , and .

Substituting theses values in above equation, we get

Thus, the thickness of the foil is 0.0015 cm.

pe = weightxheight = 2000x1000=2,000,000joules

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =