Aflea jumps straight up to a maximum height of 0.470 m . what is its initial velocity v0 as it leaves the ground?

We use kinematic equation,

Here, is final velocity and a is acceleration and s is maximum height.

Given,   and we take a as negative value of acceleration due to gravity .

At the maximum height, final velocity is zero.

Substituting these values in above equation, we get

Therefore, the initial velocity with it leave the ground is 3.03 m/s.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

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