Ahuge shell is fired from an old navy warship towards a pirate ship. if the shell is fired horizontally at a height of 25.0 meters from the water with a velocity of 75.0 m/sec a) how long will the shell take to hit the water? b) at what distance should the firing ship close to sink a shell into the pirate ship at a height of 5.00 meters above the pirate ship's water line?

The shell's vertical position at time is given by

where is the acceleration due to gravity. The shell hits the water when , so the time it takes for that to happen is

For the shell to reach a height of , it must travel for a time such that

The shell's horizontal position is given by

so that after 2.02 seconds, the warship should be at a distance

away from the pirate ship in order to hit it at the desired height.

explanation:

newton's third law, for every action there is an equal and opposite reaction.

2b2t

explanation:

2b2t