Atitanium cube contains 3.5 ×1023 atoms. the density of titanium is 4.50 g/cm3 part a what is the edge length of the cube?

0.92 cm

Explanation:

1) Equations:

Cube shape ⇒ volume = (side length) ³ ⇒ side length = ∛(volume)Density = mass / volume ⇒ volume = mass / densitymass = number of moles × atomic massatomic mass of titanium = 47.867 g/molnumber of moles = number of atoms / Avogadro's numberAvogadro's number = 6.022×10²³

2) Calculations:

number of moles = 3.5×10²³ atoms / (6.022×10²² atoms/mol) = 0.58 moles⇒ mass = 0.58 moes × 47.867 g/mol = 3.49 g⇒ volume = 3.49g / 4.50 g/cm³ = 0.78 cm³⇒ side = √ (0.78cm³) = 0.92 cm ← answer

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