In a relay race, runner a is carrying the baton and has a speed of 3.00 m/s. when he is 25.0 m behind the starting line, runner b starts from rest and accelerates at 0.100 m/s2. how long afterwards will a catch up with b to pass the baton to b?

The distance moved by runner a is calculated using the formula s = ut +

For runner a , u = 3 m/s, a = 0, s = 25 + x, where x is the distance traveled by runner b before they catch up.

So,  25 + x = 3*t

The distance moved by runner b is calculated using the formula s = ut +

For runner b , u = 0 m/s, a = 0.1, s =  x

So, x =

Substituting in the previous equation,

So they will catch up after 10 seconds.