If you throw a 0.25-kg ball with a force of 20 n, what's the acceleration of the ball?

In physics, force is equal to mass multiplied to acceleration. We are given that the mass is 0.25 kg and the force is 20 N.

F = ma
20 N = 0.25 kg * a
20 kg*m/s^2 = 0.25 kg * a
a = 20/0.25
a = 80 m/s^2

So the acceleration of the ball is 80 m/s^2.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.