How many electrons should be removed from an initially uncharged spherical conductor of radius 0.200 m to produce a potential of 5.50 kv at the surface?

To calculate the number of electrons from spherical conductor first we use the formula,

Here, k is a constant with a value of , q is the charge and r is the radius and its value of 0.200 m.

Substituting these value in above formula, we get  

or                

Now number of electron,

Hence, the number of electrons to be removed from conductor would be

Solution:

Potential is defined as

V = kq/r  

=> q= Vr/k  

= 5500 * 0.2 / 9 x 10^9 C  

= (110/9) x 10^-7  

If n = no. of electrons to be removed

So,  

n x 1.6 x 10^-19  

Therefore,

n=v/q

=> n = (110/14.4) x 10^12 electrons  

= 7.6382 x 10^12 electrons.  

This will leave an equal amount of positive charge in protons and produce the give potential on the surface of the sphere.

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explanation: