Arolling ball moves from x1 = 3.4 cm to x2 = -4.2 cm during the time from t1 = 3.2 s to t2 = 6.1 s. what is its average velocity?

Answer;

= -2.62 cm/s

Solution;

Assuming a constant acceleration (0):  

v = gradient of a displacement-time graph where displacement is on the y-axis and time is on the x- axis  

v = (x2 - x1)/(t2 - t1)  

v = (-4.2 - 3.4)cm/(6.1 - 3.2)s  

v = -7.6cm/2.9s  

v = -2.62cm/s (rounded to 2 decimal places)

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.  

well clustered together.

points close on a scatter diagram