Suppose that a shot putter can put a shot at the worldclass speed v0 = 15.00 m/s and at a height of 2.160 m. what horizontal distance would the shot travel if the launch angle θ0 is (a) 45.00° and (b) 42.00°? the answers indicate that the angle of 45°, which maximizes the range of projectile motion, does not maximize the horizontal distance when the launch and landing are at different heights.

Part a

Horizontal Distance: 22.5 m

Velocity at which shot putter shot

Angle at which it was shot =

Time of flight is given by the formula:

Taking accleration due to gravity,

Then, Horizontal distance is given as:

Part b

Horizontal distance= 23.86 m

Velocity at which shot putter shot

Angle at which it was shot =

Time of flight is given by the formula:

Taking accleration due to gravity,

Then, Horizontal distance is given as:

Therefore, although the range is maximum for part a but horizontal distance covered is smaller than in part b.

close lines strong magnet less close weaker

because if the tool that you are using is not balanced it there would be false mass.