Aparticle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. its initial position is x0 = 2.8 m at t0 = 0 s . at 1.3 s , what is the particle's position?

At time t = 1.3 s, the position of the particle is 4.3 m.

Velocity of a particle is the rate of change of its displacement.

Therefore, the velocity of the particle along the x direction is given by,

The change in the position of the particle is given by,

Integrate the equation.

Substitute and simplify.

Calculate the constant of integration C by applying initial conditions, when  t =0, x= 2.8 m.

Substitute 1.3 s for t and calculate the value of x.

The position of the particle after 1.3 s is 4.3 m

im guessing the west of station b