What is the acceleration of a toy car that starts from rest and has a speed of 0.12 m/s after 0.1?

Given: Initial velocity of toy car (u ) = 0

Final velocity of toy car (v) = 0.12 m/s

Required time (t) = 0.1 s

To find: The acceleration of the toy car.

Let the acceleration of the toy car be (a)

Formula Used: 1st kinematic equation of motion

                              v = u + at (i)

Here, all alphabets are in their usual meanings

Now, from equation (i), we shall calculate the value of 'a'.

so,                          a = (v - u) /t

or,                          a = (0.12 m/s - 0) / 0.1s

or,                          a = 1.2 m/s²

Hence, the required acceleration of the toy car will be 1.2 m/s².

he kicked it 10 feet straight up into the air? i think this works.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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