Physics, 12.07.2019 08:30 KarateKat

Aconcrete column has a diameter of 380 mm and a length of 2.6 m . if the density (mass/volume) of concrete is 2.45 mg/m3, determine the weight of the column in pounds.

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The mass is the product of the volume and dencity. The mass of the given concrete column is $1.58733\times 10^{-6} \rm \ pounds$ .

The volume of the column:

$V = \pi r^2h$

Where,

$r - \rm radius = 380 \ mm = 0.36 \ m$

h - height = 2.6 m

Put the values in the equation,

$V = \pi \times 0.19^2 \times 2.6\\\\V = 3.14 \times 0.0361\times 2.6\\\\V= 0.294\rm \ m^3$

The density of the column is 2.45 mg/m³

So, the mass of the column is

$m = 0.294 \times 2.45 \\\\m = 0.72 \rm{ \ mg} \\\\m = 1.58733\times 10^{-6} \rm \ pounds$

Therefore, the mass of the concrete column is $1.58733\times 10^{-6} \rm \ pounds$ .

Learn more about density:

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Answer from: bryantjorell

The volume of the column is

(π) · (r²) · (length) =

(π) · (0.19 meter)² · (2.6 meters) =

(π) · (0.036 m²) · (2.6 m) =

0.294 m³ .

The density is 2,450 kg/m³ (VERY very dense, heavy concrete)

so the weight of the column is (mass)·(gravity) or

(density) · (volume) · (gravity) =

(2,450 kg/m³) · (0.294 m³) · (9.81 m/s²) =

(2,450 · 0.294 · 9.81) (kg · m³· m) / (m³ · s²) =

7,066 kg-m/s² = 7,066 Newtons .

But 9.81 Newtons = 2.20462 pounds on Earth (the weight of 1 kilogram of mass), so we have

(7,066 N) · (2.205 pound/9.81 N) =

(7,066 · 2.205 / 9.81) pounds =

1,588 pounds .

Answer from: Quest

Maybe c? sorry if im wrong
An object is located 5.0 cm from a convex lens. the lens focuses light at a distance of 10.0 cm. wha

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Aconcrete column has a diameter of 380 mm and a length of 2.6 m . if the density (mass/volume) of co...

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