Physics, 13.07.2019 06:00 Izayoi

Three deer, a, b, and c, are grazing in a field. deer b is located 62m from deer a at an angle of 51° north of west. deer c is located 77° north of east relative to deer a. the distance between deer b and c is 95m. what is the distance between deer a and c?

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Answer from: yfnal3x

Based on the data given, the distance between deer A and C is 119.6 m

What is the distance between A and C?

Using the information provided, a triangle ABC is formed

Angle at A = 180° - 128° = 52° length of side AB, given as c = 62 mlength of side BC, given as a = 95 mlength of side AC, given as b = ?

Using sine rule to find the angle at B

a/sinA = c/sinC

C = sin¹ (c * Sin A/a)

C = sin¹ (62 * sin 52/95)

C = 31°

Therefore;

angle at B = 180 - (52 + 31)

angle at B = 97°

Using cosine rule to find side AC

b² = a² + c² - 2ac * cosB

b² = 95² + 62² - 2 * 95 * 62 * cos97

b = 119.6 m

Therefore, the distance between deer A and C is 119.6 m

Learn more about bearing and distance at: link

Three deer, a, b, and c, are grazing in a field. deer b is located 62m from deer a at an angle of 51

Answer from: musicqueen360

Set deer A's position to be the origin. Let be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector B-C is 95 (or C-B ). Then

$|B-C|^2=(B-C)\cdot(B-C)=B\cdot B-2B\cdot C+C\cdot C=|B|^2-2B\cdot C+|C|^2$

$|B-C|^2=|B|^2-2|B||C|\cos(180-77-51)^\circ+c^2$

$95^2=62^2-2(62)(c)\cos52^\circ+c^2$

$c^2-124\cos52^\circ c-5181=0\implies c=120\,\mathrm m$

Answer from: Quest

6 cos 34, 6 sin 34 trig

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

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