Number four says “what is the instantaneous acceleration at t = 10 s? ” can you guys with these? i will give 20 points!if you can give me the correct answers!

Explained

Explanation:

For

3)at t=0 v=4 m/s

and t=2 v=5.2 m/s

acceleration is \frac{v-u}{t}=\frac{5.2-4}{2-0}=0.6m/s^2[/tex]

5)Constant negative acceleration because slope of the graph is negative and constant.

4)

7)changing negative acceleration because slope of parabola is decreasing to zero and slope of V-t graph give acceleration

9)changing positive acceleration as the slope of graph is increasing.

10)at t=2 acceleration is because after t=4 slope is increasing and positive.