How much work is required to lift an object with a mass of 5.0 kilograms to a height of 3.5 meters? a. 17 joules b. 1.7 × 102 joules c. 1.9 × 102 joules d. 2.8 × 102 joules

B.  1.7 × 10^2 joules

Hello there.

This problem is algebraically simple, but we must try to understand the 'ifs'.

The work required is proportional to the force applied and the distance between the initial point and the end. Note: the work does not take account of the path which is described by the object, only the initial and final point. This happens because the gravitational force is generated by a conservative vector field.

Assuming the ascent speed is constant:

The force applied equals to the weight of the object. Then:

F = W = m . g

F = 5 · 9,81

F = 49,05 N

Since work equals to Force times displacement in a line, we write:

Letter B

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

more than, less

less than, more