In 1984 a team of german physicists synthesized a new element by smashing an iron-58 nucleus into a lead-208 target. if a neutron was released from the collision, what is the new nuclide

Here in all nuclear reactions we can say that mass conservation and charge conservation is always true

Here iron nuclei smashed into lead nuclei and then a new nuclei will form which will released along with a neutron

Now in this reaction mass and charge will remain conserved

mass number of iron + mass number of lead = mass number of new nuclei + mass number of neutron

58 + 208 = x + 1

x = 265

so the new nuclei formed will have mass number A = 265

now we will use charge conservation

Number of protons in iron + number of protons in lead = number of protons in new nuclei + number of protons in neutron

26 + 82 = z + 0

z = 108

so the new nuclei will form with atomic number z = 108 and mass number A = 265

If we refer periodic table to find such atom we will see that this is

so the new nuclei formed is

a.

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.