Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 1.25 kg of water decreased from 113 °c to 55.0 °c.

Energy change = -303050 J

Explanation:

the heat energy Q is given by the formula

Q= m C ΔT

m= mass of water=1.25 Kg

C= specific heat of water= 4180 J/Kg °C

ΔT= change in temperature =55-113= -58°C

Q= 1.25 (4180) (-58)

Q=-303050 J

Negative sign shows that the energy is released or lost.

a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?