An electron moves across earth's equator at a speed of 2.5 106 m/s and in a direction 35° n of e. at this point, earth's magnetic field has a direction due north, is parallel to the surface, and has a magnitude of 0.10 t. what is the force acting on the elec- tron due to its interaction with earth's magnetic field?

The force acting on the electron is 0.57*10^(-17) N.

The force on the electron is calculated by the Lauren law.

F=BQvsinθ

F=0.10*〖10〗^(-4)*1.6*〖10〗^(-19)*2.5*10^(6)sin35°

=0.57*10^(-17) N

Therefore the force on the electron is 0.57*10^(-17) N

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles