A600 n volleyball player lands from a spike attempt and immediately jumps up to try for a block. when she first contacts the ground, her velocity is 3 m/s downward, and then as she leaves the ground for the block her velocity is 4 m/s upward. her kinetic energy as she leaves the ground is

Kinetic energy of the player as she leaves the ground=490 J

Explanation:

Weight of the volley ball player= 600 N

weight= mg

m= mass

g= acceleration due to gravity=9.8 m/s²

so 600= m (9.8)

m=61.2 kg

Now the kinetic energy is given by KE= 1/2 mv²

v= velocity of the player as she leaves the ground= 4 m/s

KE= 1/2 (61.2)(4)²

KE= 490 J

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