The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. a distance of 3.5 × 10–5 m separates the plates. the plates are separated by a dielectric made of teflon, which has a dielectric constant of 2.1. what is the capacitance of the capacitor?.18

the capacitance of the capacitor= C=0.18 μ F

Explanation:

The capacitance of a parallel plate capacitor is given by

K= dielectric constant=2.1

ε= 8.85 x 10⁻¹² C²/Nm²

a= area of plates=0.063 x 5.5= 0.302 m²

d= distance between the plates= 3.5 x 10⁻⁵m

C= (2.1)(8.85 x 10⁻¹²)(0.302)/ (3.5 x 10⁻⁵)

C=1.8 x 10⁻⁷F

C=0.18 μ F

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