Until a train is a safe distance from the station it must travel at 5 m/s. once the train is on open track it can speed up to 45 m/s. if it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (round your answer to the nearest whole number.) 4 m/s2 5 m/s2 6 m/s2 7 m/s2

the acceleration of the train is 5 m/s²

Explanation:

initial velocity= Vi= 5 ms

final velocity= Vf= 45 m/s

time= t= 8 seconds

using kinematic equation Vf= Vi +at

45= 5+a (8)

8 a = 45=5

8a= 40

a= 40/8

a= 5m/s²

So the acceleraton of the train is 5m/s²

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards