You pull with a force of 255 n on a piece of luggage of mass 68 kg, but it does not move. if the coefficient of friction between the luggage and the floor is 0.7, what is the force of static friction acting on the luggage?

The force of static friction acting on the luggage =255 N

Explanation:

Applied force= 255 N

mass of luggage=68 kg

coefficient of friction= μ=0.7

Normal force=N = mg

N= 68(9.8)=666.4 N

now the force of friction is given by

Ff= μN

Ff=0.7 (666.4)

Ff=466.5 N which is greater than the applied force.

When the applied force is less than the force of friction, in that case

force of friction= applied force

Thus the force of station friction acting on the luggage = 255 N

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.