1kg of ice at 0° c is mixed with 9 kg of water at 50° c (the latent heat of ice is 3.34x105 j/kg and the specific heat capacity of water is 4160 j/kg). what is the resulting temperature?

ice:

mass (m) =    1 kg

Initial Temperature (T) = 0    ° C

Latent heat (L) =  3.34 * 105 J/kg

Water:

mass (m) = 9 kg

Initial Temperature (T) = 50 ° C

Specific heat capacity (c) = 4,160 J/kg

First you must find the amount of heat required for the ice to turn into water (Q is heat)

Q = mL

Q = 1 * (  3.34 * )

Q = 3.34 *   J

1 kg of  ice needs 3.34 *   J of energy to convert into water

The heat lost by the water is equal to the heat gained by the ice.

Heat can be found using the equation: Q = mcΔT therefore...

mcΔT (water) = mcΔT (ice)

9 * 4,160(50 - x) = 1 * 4,160(x - 0) + 3.34 *

You need to add the heat needed for the ice to convert into the water (3.34 * J) to the ice side of the equation, because when we get the final temperature the ice will be converted into water.

x = 36.97

The resulting temperature is 36.97  ° C

I hope this helped!

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The final temperature of the mixture is 46.2°C.

According to the theory of heat exchange, heat absorbed by ice is equal to the heat given by water. Ice absorbs heat to first melt at a constant temperature of 0°C and then water at 0°C increases its temperature to the final temperature T. The amount of heat for this process is provided by hot water at 50°C, which cools down to the final temperature of the mixture T.

Heat absorbed by ice is given by,
=(1 kg)(3.34*10^5 J/K)+(1 kg)(4160 J/kg)(T-0)
=3.34*10^5+4160T
" alt=" Q_{a} =m_{ice} *L+m_{ice}*c_{w} (T-0)" />
=(1 kg)(3.34*10^5 J/K)+(1 kg)(4160 J/kg)(T-0)
=3.34*10^5+4160T
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heat given by water is given by

Equating both the equations and solving for T,

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i would like to make dinner for my mom, dad, and sister

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.